What will be printed by the following C code?

In the given C code, if there are variables declared but not initialized, their values will default to whatever happens to be in the memory at that location, leading to what is often referred to as "garbage values."

When a program declares a variable without initializing it, the C standard does not define what values those variables will hold; they can contain any leftover information that was previously at that memory location. Therefore, if the code attempts to print these uninitialized variables, the output will consist of these indeterminate values, which we term "garbage."

In this scenario, assuming the code attempts to output two uninitialized variables, the output you'll see will reflect the state of the memory at those locations at the time of the print statement. As a result, it could easily print "0" if the memory happened to have a zero in it, but since they are technically uninitialized, they may print arbitrary values instead.

The chosen answer reflects the occurrence of one or more of these uninitialized variables. Therefore, the output being described as "0 Garbage" indicates that one of those variables happened to have a zero value while the other did not, thus confirming that uninitialized variable values can lead to unexpected and unpredictable output in C.