What is the output of the following program that dereferences a pointer?

In the context of dereferencing pointers in programming, particularly in languages like C or C++, the program likely accesses a memory location through the pointer and retrieves a value stored at that location. If the program is designed correctly and the pointer has been assigned to a valid memory address where the integer value 64 is stored, then dereferencing this pointer will yield the value 64.

Dereferencing means accessing the value at the address that the pointer points to. When the program runs successfully, and if the pointer holds the address of an integer with the value 64, dereferencing it will result in 64 being the output of the program.

The other potential outputs like 320, invalid memory access, or 0 would depend on different scenarios, such as the pointer pointing to a different integer value, referencing an unallocated or deallocated memory space, or specifically being initialized to zero. However, the specific mention of 64 suggests that the pointer indeed points to a valid location containing the integer 64, thus making this the correct output of the program.