What is the expected output of the swap function if called in the main function?

Disable ads (and more) with a membership for a one time $4.99 payment

Study for the University of Central Florida EGN3211 Final Exam. Practice with flashcards and multiple choice questions, each question with hints and explanations. Prepare effectively and boost your engineering analysis and computation skills for success!

In order to understand why the expected output of the swap function would be that "X is 5 Y is 10", we need to consider how the swap function is typically implemented in programming. If the swap function is designed to exchange the values of two variables, it generally takes two references or pointers to those variables as its parameters.

Assuming the main function initializes the variables X and Y with the values 10 and 5, respectively, when the swap function is called with those variables, the function would execute code that exchanges their values. Specifically, it would assign the value of X to Y and the value of Y to X, effectively swapping them.

Once the swap operation completes, if you were to print the values of X and Y, you would observe that X now holds the value that was previously in Y (5), and Y now holds the value that was previously in X (10). This illustrates the fundamental behavior of the swap function: it allows for the interchanging of two variable values during program execution.

In this context, it is clear that the expected output confirms the correct state of the variables after the swap operation is performed.