If an array begins at memory address 4300, what will be the output of the printf statement?

To determine the output of the printf statement regarding the memory addresses in an array, we need to understand how arrays are stored in memory. When an array is declared, its elements are stored in contiguous memory locations.

Assuming the array elements are integers, each integer typically occupies 4 bytes in memory (this can vary with data type and system architecture, but for the sake of this question, we will use the common 4-byte integer representation). If the array begins at memory address 4300, the first element resides at that address.

The first output value corresponds to the address of the first element, which indeed is 4300.

The second element in the array will then be located at the address that adds the size of one integer (4 bytes) to the starting address. Thus, the second element will be at address 4300 + 4 = 4304.

The third value in the output relates to the first element again, reaffirming that the output can reference the same memory location multiple times when using proper array indexing.

Given that the question appears to provide outputs that include the starting address and the next immediate memory address (without consideration of explicitly stated array indices), the values produced by the printf statement would list the